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Math Induction

  1. Feb 1, 2005 #1
    I was trying to help a friend do the following problem

    Prove with induction

    Sum of [tex] i^5 [/tex] from 1 to n =

    [tex] \frac{n^2(n+1)^2(2n^2+2n-1}{12} [/tex]

    we got it to

    [tex] \frac{(k+1)^2(k+2)^2(2k^2+4k+2)+2k+1}{12} [/tex] but we can't seem to get it to go back to the orginal equation when you substitue k+1 into the orignal formula
  2. jcsd
  3. Feb 1, 2005 #2
    you might made an algebra mistake

    try plug an integer into k.... you'll see the numerator is odd and the denominator is even, which mean the answer is not even an integer......

    check your algebra.................
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