# Math Induction

1. Feb 1, 2005

### Tom McCurdy

I was trying to help a friend do the following problem

Prove with induction

Sum of $$i^5$$ from 1 to n =

$$\frac{n^2(n+1)^2(2n^2+2n-1}{12}$$

we got it to

$$\frac{(k+1)^2(k+2)^2(2k^2+4k+2)+2k+1}{12}$$ but we can't seem to get it to go back to the orginal equation when you substitue k+1 into the orignal formula

2. Feb 1, 2005

### vincentchan

you might made an algebra mistake

try plug an integer into k.... you'll see the numerator is odd and the denominator is even, which mean the answer is not even an integer......