Can you figure out how to read this equation as a limerick?(adsbygoogle = window.adsbygoogle || []).push({});

[tex]\int_{1}^{\sqrt[3]{3}}t^2\ dt\cdot\cos\left(\frac{3\pi}{9}\right)=\ln \sqrt[3]{e}[/tex]

Answer (in white, select to read):

Integral t-squared dt

From 1 to the cube root of 3

Times the cosine

Of 3 pi over 9

Equals log of the cube root of e

(It's true too)

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# Math limerick

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