- #1

denian

- 160

- 0

find the square root of 11 - 6*(square root of 2) and write the solution in surd notation.

answer provided by the book :

3 - (square root of 2)

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- Thread starter denian
- Start date

- #1

denian

- 160

- 0

find the square root of 11 - 6*(square root of 2) and write the solution in surd notation.

answer provided by the book :

3 - (square root of 2)

- #2

dduardo

Staff Emeritus

- 1,901

- 3

Why don't you try using binomial expansion to solve the problem.

sqrt(11-6*sqrt(2)) = sqrt(11)*(1+((-6/11)*sqrt(2))^(1/2)

x = (-6/11)*sqrt(2)

n = 1/2

1 + n*x + (n*(n-1)*x^2)/2! + (n*(n-1)*(n-2)*x^3)/3! + ....

- #3

gnome

- 1,037

- 1

(a - b√2)

What happens when you multiply out

(a - b√2)

Can you solve for a and b?

Does that help?

- #4

denian

- 160

- 0

yup.

thanks.

thanks.

- #5

denian

- 160

- 0

but i use ( [squ] x - [squ] y ) to the power of two instead.

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