Math problem

  • Thread starter eahaidar
  • Start date
71
1

Main Question or Discussion Point

Hello everyone
I want to solve this equation
F(x)=Ax/((bx*x)+c =constant which is an odd function in which we get same positive and negative solutions for each F
But If I solve his equation I get two different x values for The same F any suggestions??
Thank you
 

Answers and Replies

32,942
4,653
Hello everyone
I want to solve this equation
F(x)=Ax/((bx*x)+c =constant which is an odd function in which we get same positive and negative solutions for each F
But If I solve his equation I get two different x values for The same F any suggestions??
Do you mean two different x values for the same value of what you're calling the constant?

Graph y = x/(x^2 + 1) to get an idea of what your function F looks like.
 
71
1
First thank you for the reply
Second yes these are all constants but what I am asking about is how come if I solve it analytically I would not get 2 values on x same but opposite to each other
But different values of x
 
Simon Bridge
Science Advisor
Homework Helper
17,823
1,640
yes these are all constants
... surely you are treating x as a variable?
You seem to be wanting to solve: $$a=\frac{x}{bx^2+c}$$... here a=<constant>/A which is also a constant.

This becomes ##abx^2-x+ac = 0## which is a quadratic equation.

You are getting two possible values of x for given values of a,b, and c because there are two possible values that make the relation true. What is the problem?

Your concern seems to be that you are getting ##\pm## <the same number> as the roots ... if so, then please show your working.
 
Last edited:

Related Threads for: Math problem

  • Last Post
Replies
5
Views
2K
  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
5
Views
2K
  • Last Post
Replies
16
Views
7K
  • Last Post
Replies
3
Views
4K
  • Last Post
Replies
4
Views
2K
  • Last Post
Replies
6
Views
2K
Top