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Math puzzle question

  1. Jul 1, 2003 #1
    hi! i've got a puzzle.can u solve it?here it is:

    a father has 90 apples.he has 3 children: A,B,and C.one day, the father told his children this:

    Come here A, sell this 50 apples with the same procedure like your 2 brothers that result the same income
    Come here B, sell this 30 apples with the same procedure like your 2 brothers that result the same income
    Come here C, sell this 10 apples with the same procedure like your 2 brothers that result the same income

    how can u sell it to have the same income between those three with the same procedure?

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    [​IMG]
    Ibnu Sina (Avicenna in the West)
    The Teacher of Kings
     
  2. jcsd
  3. Jul 1, 2003 #2

    MSI

    User Avatar

    as i understand i think each son could sell the apples for free so they will get the same income
    or:
    a=1/5 $ "for each apple"
    b=1/3 $
    c=1 $

    am i right?
    because i feel i am in a bigggggg wrong
     
  4. Jul 1, 2003 #3
    not quite right.giving for free is not selling.as i said, they have to sell it.and the 1/5,1/3,and the 1 $ thing is also not the answer.its not the same procedure. ifyou sell it like that, the procedure would not be the same.the procedure has to be the same.

    --------------------
    [​IMG]
    Ibnu Sina (Avicenna in the West)
    The Teacher of Kings
     
  5. Jul 1, 2003 #4
    well, how about exagerating and selling each apple for [oo] $ (or whatever currency they used)???
     
  6. Jul 1, 2003 #5
    ow c'mon, what apple costs [oo] $ ? this a real thing and can be done in a real life too.and this doesn't has a connection wtih currencies.

    --------------------
    [​IMG]
    Ibnu Sina (Avicenna in the West)
    The Teacher of Kings
     
  7. Jul 1, 2003 #6
    What do you mean by procedure ?
     
  8. Jul 1, 2003 #7

    jb

    User Avatar

    sell them by the pound
     
  9. Jul 1, 2003 #8
    I agree.
     
  10. Jul 1, 2003 #9
    Each sell a bag of apples for $10.
    Each bag has all the apples given to each son.
     
  11. Jul 1, 2003 #10
    guess my puzzle has some holes in it.i think it could be answered by daves answer, but thats not what i mean.well, i think i need to expose it, cause the inperfection of my puzzle that has been found by dave.my version is:


    -put those apples in a bag with each bag contains 7 apples.sell it for 1 $
    -the rest of apples,sell it with 7 $


    now u can calculate that

    A= (1$ x 7 bags) + 3$ x 1 apple = 10$
    B= (1$ x 4 bags) + 3$ x 2 apples = 10$
    C= (1$ x 1 bag) + 3$ x 3 apples = 10$

    thats it.good for u dave!
    --------------------
    [​IMG]
    Ibnu Sina (Avicenna in the West)
    The Teacher of Kings
     
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