Not sure if anyone plays craps here, but I think one of the probabilities is wrong.The C and E bet which is a single roll on craps (2,3,12, four total possible combinations for 2 dice which has 36 total possible combinations) or on 11 (yo) which has two combinations for a total of six combinations. Your bet is split between the two bets so this bet must an even number, split between craps and 11. If 11 rolls you have 15:1 payout on half your bet and the other on craps lose. If craps (2,3,12) is rolled you have a 7:1 payout on half your money and lose the half on 11. For example if you bet $2 on the C and E the dealer will put $1 on each. If craps is rolled you get $7 - $1 you lose on 11 so total profit is $6, you can take the $1 on craps back if you wish. If an eleven is rolled you get 15:1 on your $1 not $2, because the bet is split so you would profit $14 dollars $15 - $1 you had on C (craps). Because you lose half your money when this bet wins and lose everything when a number other than craps or 11 is rolled, shouldn't the house edge be better than 11.11% (as in worse for the player higher house edge than 11.11%)? If you bet on the 11 alone you get 15:1 payout when the true odds are 17:1 for an 11.11% house edge. How can this be the same if you are making a bet on the C and E where you lose half your bet even if you win? Are the odds on Wikipedia right?