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Math question

  1. Dec 5, 2007 #1
    d=n^2 - 3n / 2

    where d = number of diagonals
    and n = the number of sides of the polygon.

    A polygon has 119 diagonals, how many sides does it have?

    119 = n^2 - 3n / 2

    I am not sure how to do this? can someone please help?

    sorry this isn't physics related

    I know I need to use the quadratic formula, but how?
     
  2. jcsd
  3. Dec 5, 2007 #2

    rl.bhat

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    Homework Helper

    d=n^2 - 3n / 2 this should be d = ( n^2 - 3n)/2
    Wright the given equation 119 = n^2 - 3n / 2 as 2*119 = n^2 - 3n and solve the quadritic equation to get the value of n.
     
  4. Dec 5, 2007 #3
    thank you very much
     
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