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help me i dont know where i must to posting this task
if
8+4=12
7+2=9
2+3=6
6+5=10
9+5 = ?
if
8+4=12
7+2=9
2+3=6
6+5=10
9+5 = ?
figured numberI don't understand...
2+3=5 and 6+5=11 but you've shown otherwise, and I don't understand how we are now going to conclude what 9+5 is equal to based on this wrong maths.
Much of this doesn't make any sense. 2 + 3 = 5, not 6, and 6 + 5 = 11, not 10.help me i dont know where i must to posting this task
if
8+4=12
7+2=9
2+3=6
6+5=10
9+5 = ?
And none of the above makes any sense.figured number
13+7=5
15+6=9
10+7=11
8+8=11
this for next example
I assume that this is some algebraic structure in which the digits do NOT refer to the usual integers and/or "+" is not ordinary "add". But the difficulty is, what can we take to be true? Are we to assume this operation is commutative? Associative?help me i dont know where i must to posting this task
if
8+4=12
7+2=9
2+3=6
6+5=10
9+5 = ?
I'm going to throw in a wild guess and say 14.help me i dont know where i must to posting this task
if
8+4=12
7+2=9
2+3=6
6+5=10
9+5 = ?
If each symbol stands for a particular, but different true decimal digit and '+' is a sign for regular addition, then the above conditions do not have a solution. I have check all 151,200 possibilities by brute force.help me i dont know where i must to posting this task
if
8+4=12
7+2=9
2+3=6
6+5=10
9+5 = ?
That's what I was thinking.If each symbol stands for a particular, but different true decimal digit and '+' is a sign for regular addition, then the above conditions do not have a solution. I have check all 151,200 possibilities by brute force.
That thought crossed my mind, too.But I have a totally new theory, the OP is just trolling us.
my teacher just sayThat's what I was thinking.
Essentially we would be solving
a+b=c
d+e=f
e+g=h
...
etc.
Without being given any further information as to how these symbols interact with each other.
But I have a totally new theory, the OP is just trolling us.
Clarify? This makes no sense to me. I still think 14's a good answer."do not be fooled pattern placement sequence similarities.
without divisors and a deduction"
Then the troll wins! :yuck:Well, I spent two hours thinking about the problem, took a few hours off, then continued for another hour but I'm still stumped. Is there any more to the sequence?
Z
If each symbol stands for a particular, but different true decimal digit and '+' is a sign for regular addition, then the above conditions do not have a solution. I have check all 151,200 possibilities by brute force.
I too thought the same thing. How did you come up with 151,200 possibilities btw?That's what I was thinking.
Essentially we would be solving
a+b=c
d+e=f
e+g=h
...
etc.
I too thought the same thing. How did you come up with 151,200 possibilities btw?
The following digits appear: {0, 1, 2, 3, 4, 5, 6, 7, 8 , 9}, i.e. all ten of them. Let us make the correspondence to variables:help me i dont know where i must to posting this task
if
8+4=12
7+2=9
2+3=6
6+5=10
9+5 = ?