Solve Math Word Problem: Bickford & Shawn Speed & Times

In summary, the conversation is about finding the rates and times of two boys, Bickford and Shawn, who are traveling to different locations. Bickford travels twice as fast as Shawn, and using the formula d = rt, we can set up two equations with two unknowns to solve for their rates and times. Bickford's speed is 2v and his time is t-2, and Shawn's speed is v and his time is t. By setting up the equations 320 = 2v(t-2) and 240 = vt, we can solve for the values of v and t.
  • #1
bushman91
5
0
Bickford traveled twice as fast as Shawn traveled. Thus, Bickford could travel the 320 miles to the reef in only 2 hours less than it took shawn to travel the 240-miles to Jane's house. Find the rates and times of both boys.

Just having problems figuring out the formula and how to set it up.

So Shawn is x
Which would make Bickford 2x
 
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  • #2
Use [tex] d = rt [/tex]. So for Bickford, [tex] 320 = 2v(t-2) [/tex] and for Shawn [tex] 240 = vt [/tex].
 
Last edited:
  • #3
Please explain how you set that up and the what the variables represent
 
  • #4
Distance is defined as speed [tex]\times [/tex] time . Let [tex] v [/tex] be the speed of Shawn. Then [tex] 2v [/tex] is the speed of Bickford. Also, let [tex] t [/tex] be the time it takes Shawn to travel to Jane's house. Using the equation [tex] d = vt [/tex] (where v is the speed) we can set up two equations with two unknowns.

Bickford's speed is [tex] 2v [/tex] and his time is [tex] t-2 [/tex] (two hours less time than Shawn) and he travels 320 miles. So we have [tex] 320 = 2v(t-2) [/tex].

Shawn's speed is [tex] v [/tex] and his time is [tex] t [/tex] and he travels 240 miles. So we have [tex] 240 = vt [/tex]. Can you solve for [tex] v [/tex] and [tex] t [/tex]?
 
  • #5
thanks for the help, I should be able to get it now
 

What is the Bickford & Shawn Speed & Times math word problem?

The Bickford & Shawn Speed & Times math word problem involves two friends, Bickford and Shawn, who are competing in a speed race. The problem presents different scenarios and asks for the speed and time of each friend.

What are the steps to solving the Bickford & Shawn Speed & Times math word problem?

The first step is to identify the given information, including the distance, speed, and time for each friend. Then, use the appropriate formula to calculate the missing values. Finally, check your work and make sure the answers make sense in the context of the problem.

What formulas are needed to solve the Bickford & Shawn Speed & Times math word problem?

To calculate distance, use the formula d = rt, where d is distance, r is rate (speed), and t is time. To calculate speed, use the formula r = d/t. To calculate time, use the formula t = d/r.

How can I check my work when solving the Bickford & Shawn Speed & Times math word problem?

One way to check your work is to plug your answers back into the original problem and see if they make sense. For example, if the problem states that Bickford ran for 2 hours at a speed of 5 miles per hour, then the distance he ran should be 10 miles.

What are some tips for solving the Bickford & Shawn Speed & Times math word problem?

Some tips for solving this math word problem include carefully reading the problem and identifying the given information, using the correct formulas, and checking your work. It can also be helpful to draw a diagram or create a table to organize the information and make it easier to solve the problem.

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