# Mathematica Problem

1. Jan 25, 2010

I just got Mathematica last night and am trying to use it for the first time. I'm trying to plot a graph $$f(x)=K(1-x)^{\frac{-3}{8}}$$ but it's not working right. I tried first with K = 325 (for physical reasons) and the graph started negative at x=0. If I choose K to be almost anything other than 325 the graph starts at 0 which is also wrong. The command I gave was Plot[325(1-x)^(-3/8), {x,0,0.9}]. Did I do something wrong?

2. Jan 25, 2010

### abc007

Last edited by a moderator: May 4, 2017
3. Jan 25, 2010

### CompuChip

Are you sure it starts at 0?
Or does it start at the crossing of the axes? Look carefully if the intersection point is indeed (0, 0), and not (0, 325).
If you insist on having it in the origin, usr

Code (Text):

Plot[325(1-x)^(-3/8), {x,0,0.9}, AxesOrigin->{0, 0}]

4. Jan 25, 2010