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Mathematical Functions

  1. May 26, 2003 #1
  2. jcsd
  3. May 26, 2003 #2
    Seem to work. Although could just state the elementary formulae used. Having said that, it depends upon the audience.
     
  4. May 26, 2003 #3
    most people wouldn't know how to use the formula if i state it...
     
  5. May 27, 2003 #4
    i tried the first method


     
  6. May 27, 2003 #5
    because the semiperimeter is 3, thus when you apply it to Heron's Formula it has a 0 term in the squareroot, since it's all multiplication, any term multiply by 0 would produce 0. Thus my functions works fine.
     
  7. May 27, 2003 #6

    Hurkyl

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    Or for a more "obvious" reason, if you try to draw a 3-1-2 triangle, you'll find its height is 0.
     
  8. May 27, 2003 #7

    As it has to be as 2+1 = 3.
     
  9. May 27, 2003 #8
    oops, silly me. it was late and my brain wasnt working very well
     
  10. May 28, 2003 #9
    Excuse...
     
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