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Homework Help: Maths about ratio

  1. Apr 18, 2005 #1
    1)If (x+y-z)/3
    then x:y:z=

    The answer for the above question is option B. But I don't know how to solve this kind of questions. Can anyone tell me what should I do in the first step? Thanks for answering my question.
  2. jcsd
  3. Apr 18, 2005 #2
    step 1: 3*4*5=60
    step 2: 20x+20y-20z=15y+...
  4. Apr 18, 2005 #3


    That's what I solve from the above equation. After that, what should I do? Thanks.
  5. Apr 18, 2005 #4


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    Science Advisor

    Did you see AntonVrba's response? Since you asked to choose among different possible answers, the simplest thing to do is try each.
    x= 3, y= 4, z= 5 ARE in ratio 3:4:5. Do those numbers satisfy the original equations?

    If not try x= 8, y=7, z= 9, etc.
  6. Apr 18, 2005 #5
    no need for trial and error of trying given posibilities, you can calculate
    from the three relationships x,y,z that you already have solved by substituting first y and then for second z in the first of your equations.

    x = 4z - 4y
    = 4z - 28z + 28x
    24z = 27x
    8z = 9 x
    8/9 = x/z or 8:9 = x:z


    x = 4z - 4y
    x = 36x - 36y - 4y
  7. Apr 18, 2005 #6


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    Science Advisor

    Yeah, but it works and thought it would be simpler for fork.
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