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- #1

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- #2

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- #3

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[tex]n = \frac{(\frac{a}{b})}{(\frac{c}{d})}[/tex]

[tex]n\left(\frac{c}{d}\right) = \frac{a}{b}[/tex]

[tex]nc = \frac{ad}{b}[/tex]

[tex]n = \frac{ad}{bc} = \left(\frac{a}{b}\right) \times \left(\frac{d}{c}\right)[/tex]

- #4

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Thanks for the proof abacus, well appreciated makes things clearer for me.

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