Bbss with bbss, what to do? In goats, black color (B) is domnant over red (b), and solid color (S) is dominant over spotted (s). If the offspring between Bbss and bbss individuals are mated with each other, what fraction of their offspring will be expected to be black and spotted? Assume these genes are unlinked. A. 1/16 B. 9/16 C. 1/9 D. 3/16 E. 3/4 I think that the answer is 3/4, but I'm not sure and I don't know the right answer. The possible gametes that I get for Bbss are Bs and bs. The possible gametes that I get for bbss is just bs. The possible offspring of these gametes that I get are: Bbss and bbss, which are the same as the parents. This is were I get stuck. I don't know how to do it using the punnet square or how to use probability in this problem. Can anyone show me please? How do you do this problem?