- #1

dRic2

Gold Member

- 816

- 198

Here's what I have to do:

1) I arbitrary give a first value to the variable ##x_b##. Let's say ##x^{(0)}_b = 0.3##

2) I find ##x_D## by evaluating this integral:

$$ln(\frac {52.32} {100}) = \int_{0.5}^{x^{(0)}_b} \frac {dx} {x^{(0)}_D - x}$$

3) I use the value I got for ## x^{(0)}_D## to evaluate ##y^{(0)}_n##

$$y^{(0)}_n = f(x^{(0)}_D, x^{(0)}_b)$$

4) I check if ##x^{(0)}_D - y^{(0)}_n = 0## then I stop, otherwise I have to choose an other ##x^{(1)}## and start iterating again.

In matlab:

and I call this with:

I keep getting a warning that the integral my not exist and fsolve won't start...

Any help?

1) I arbitrary give a first value to the variable ##x_b##. Let's say ##x^{(0)}_b = 0.3##

2) I find ##x_D## by evaluating this integral:

$$ln(\frac {52.32} {100}) = \int_{0.5}^{x^{(0)}_b} \frac {dx} {x^{(0)}_D - x}$$

3) I use the value I got for ## x^{(0)}_D## to evaluate ##y^{(0)}_n##

$$y^{(0)}_n = f(x^{(0)}_D, x^{(0)}_b)$$

4) I check if ##x^{(0)}_D - y^{(0)}_n = 0## then I stop, otherwise I have to choose an other ##x^{(1)}## and start iterating again.

In matlab:

Code:

```
function out = my_int(xD, xB)
fun = @(xD) 1./(xD - x)
out = log(52.32/100) - integral(fun, 0.5, xB);
end
function out = system(xb)
find_xD = @(xD_) my_int(xD_, xb);
xD = fzero(find_xD, 0.7);
% other lines of the code
% where I calculate y_n
out = y_n - xD;
end
```

and I call this with:

Code:

`fsolve(@system, 0.3);`

I keep getting a warning that the integral my not exist and fsolve won't start...

Any help?

Last edited: