Filling an n4 x n4 Matrix with a 4 x 4 Matrix

[ziad1985]

I have a [4 X 4] matrix , and another one which is [n4 X n4] n is an integer.
my question is there a way to fill the [n4 X n4] with n times the small [4 X 4] one.
meaning if the [4 X 4] is a
what i want to do is
a a a a
a a a a
a a a a
a a a a
n is 4 , so it's [16 X 16]
any certain function to use ? or it would have to be a For Loops to use ?

 

[doodle]

I think repmat() is what you need. Type help repmat at the prompt for instructions on the use.

 

[tacman]

Yes, there is a way to fill the [n4 X n4] matrix with n times the [4 X 4] matrix. This can be achieved by using a nested for loop. The outer loop will iterate n4 times to fill the rows of the larger matrix, while the inner loop will iterate n4 times to fill each row with n copies of the [4 X 4] matrix.

In pseudocode, it would look something like this:

for i from 0 to n4-1:
for j from 0 to n4-1:
for k from 0 to 3: (since the [4 X 4] matrix has 4 rows)
for l from 0 to 3: (since the [4 X 4] matrix has 4 columns)
[n4 X n4] matrix[i*4 + k][j*4 + l] = [4 X 4] matrix[k][l]

This will fill the [n4 X n4] matrix with n times the [4 X 4] matrix. You can also use other programming concepts like indexing and slicing to achieve the same result.