- #1

mr_coffee

- 1,629

- 1

-2x1 + x2 = 5

6x1 - 3x2 = -15

[tex]\left( {\begin{array}{*{20}c}

{-2} & 1 & 5 \\

6 & -3 & {-15}\\

\end{array} } \right)[/tex]

I then solved it down too:

[tex]\left( {\begin{array}{*{20}c}

{-2} & 1 & 5 \\

0 & 0 & 0\\

\end{array} } \right)[/tex]

It wants me to put it parametric form:

so i did the following:

-2x1 + x2 = 5

2x1 = -5 + x2

x1 = (-5+x2)/2

let x2 = s;

[-5/2] + [1/2] S

[0 ] [0 ]

but its wrong! any ideas? Thanks