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Matrices and transformations

  1. Feb 6, 2006 #1
    I just wanted to know how I could work out the angle of rotation from the following matrix -0.6, -0.8 (top) and 0.8, -0.6 (bottom)??? :frown:

    Is this possible or am I missing something here?
     
  2. jcsd
  3. Feb 6, 2006 #2

    matt grime

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    Rotation matrices have a certain form (cos, sin, -sin, cos) or something. You can do inverse sin, or cos, so all is well.
     
  4. Feb 6, 2006 #3
    right,

    so I get:

    a (top left of matrix) => cos-1 (-0.6) = 126.9 degrees

    b (top right of matrix) => -sin-1 (-0.8) = 53.1 degrees

    c (bottom left of matrix) => sin-1 (0.8) = 53.1 degrees

    d (bottom right of matrix) => cos-1 (-0.6) = 126.9 degrees

    What is the overall transformation? Is is 126.9 + 53.1 = 180 degrees???
     
  5. Feb 6, 2006 #4
    It can't be 180 degrees, since that would give you a matrix of (-1, 0 , 0, -1), in the order, top left, top right, bottom left and bottom right, i think. I think that the angle of rotation from the positive x-axis is 126.9 degrees, but I'm not entirely sure.
     
  6. Feb 6, 2006 #5

    matt grime

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    It's either 123.9 or 56.1 (and of course they add up to 180), check the correct form of a rotation matrix in your notes.
     
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