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Matrix Problem

  1. Oct 17, 2012 #1
    1. The problem statement, all variables and given/known data
    I attached the problem as a file


    2. Relevant equations



    3. The attempt at a solution
    The way I tried to solve this was to write out a few multiplications and find a pattern. I got the right answer, but I was wondering if there was more of a precise way of doing it; or would the procedure that I used be acceptable for a first course in Discrete Mathematics?
     

    Attached Files:

  2. jcsd
  3. Oct 18, 2012 #2
    After you found the rule, try proving it using induction. Show first that it holds for n=2 and then show if it holds for n, then it also holds for n+1.
     
  4. Oct 18, 2012 #3
    Or use orthogonalisation(writing A in the form of [itex]C^{-1}BC[/itex]) in which B is an orthogonal matrix. Then the multiplication can be simplified into: [itex]A^n = C^{-1}B^{n}C[/itex].
     
    Last edited: Oct 18, 2012
  5. Oct 18, 2012 #4
    Thank you, Clamtrox.

    Raopenq, we haven't learned about orthogonalisation.
     
  6. Oct 18, 2012 #5
    Good, because the matrix is not diagonalizable :) If you want to understand a bit more what's happening here, it might be useful to write the matrix as
    [tex]A = \left( \begin{array}{cc} 1 & 1 \\ 0 & 1 \end{array} \right) = \left( \begin{array}{cc} 1 & 0 \\ 0 & 1 \end{array} \right) + \left( \begin{array}{cc} 0 & 1 \\ 0 & 0 \end{array} \right) [/tex]
    and then look how these two matrices multiply together.
     
  7. Oct 18, 2012 #6

    Zondrina

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    Start by multiplying out A2 and A3, what do you notice about the entry a12? Also, use the fact that matrix addition is entry wise.

    Both of these should allow you to complete a full induction proof.
     
  8. Oct 18, 2012 #7
    oops sorry...
     
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