Matter-antimatter energy

  • Thread starter abohn1
  • Start date
  • #1
8
0
Science-fiction movies and TV shows often refer to antimatter propulsion
drives. This is not as far-fetched as it may seem. In a matter-antimatter
annihilation event, a particle and its antiparticle annihilate each other and
release all of their mass energy (such as in the reaction p+p→2γ, for
example). How many of these matter-antimatter annihilation events are
needed to get our kWh of energy? And what is the total mass of protons and
antiprotons required to do this?

Hint: The antiproton has the same mass as that of the proton,
938.3 MeV/c2 = 1.6726ï10-27 kg.

I'm not great with the whole concept of anti-matter, any help please? Such as equations to use and general concepts?
 

Answers and Replies

  • #2
tiny-tim
Science Advisor
Homework Helper
25,832
251
Welcome to PF!

Hi abohn1! Welcome to PF! :smile:

(try using the X2 tag just above the Reply box :wink:)

You don't need to know anything about anti-matter (and it's the same as matter, anyway :wink:) …

just use e = mc2. :smile:
 
  • #3
actually antimatter-matter collisions create so much power! one particle of antimatter with one particle of matter will create 200 times the energy of a hydrogen bomb!!!!!!
 

Related Threads on Matter-antimatter energy

  • Last Post
Replies
14
Views
3K
  • Last Post
Replies
7
Views
3K
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
2
Views
1K
Replies
4
Views
2K
  • Last Post
Replies
1
Views
1K
Replies
2
Views
3K
  • Last Post
Replies
14
Views
4K
Replies
1
Views
578
Top