Max Height of a Projectile

  • Thread starter Bobbert
  • Start date
  • #1
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Homework Statement


Find the max height of a projectile fired at an angle of 30 degrees if it's inital speed is 0.714m/s.
(this is a lab so I have other data that might be needed)

Homework Equations


V22=V12+2ad

The Attempt at a Solution


V22=V12+2ad
0=(0.714sin30o)2+2(-9.81)(d)
d=19.62-0.127449
d=19.49m

Now this answer is not practical at all. There is no way my projectile went that high. Maybe a couple meters, but not 19.5m. Where did I go wrong?
 

Answers and Replies

  • #2
LowlyPion
Homework Helper
3,090
4
3. The Attempt at a Solution
V22=V12+2ad
0=(0.714sin30o)2+2(-9.81)(d)
d=19.62-0.127449

d=19.49m

Now this answer is not practical at all....
Maybe it's your math that isn't practical?

Shouldn't you get a result that is a small number divided by a big number?
 
  • #3
rock.freak667
Homework Helper
6,230
31
If v2=0

then 0=V12-2(9.81)d

[tex]d=\frac{V_1^2}{2(9.81)}[/tex]
 
  • #4
16
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wow, it is way to late. How did I mess that up.
 

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