# Homework Help: Max Magnetic Force

1. Jul 15, 2008

### kdrobey

1. The problem statement, all variables and given/known data
In a television set, electrons are accelerated from rest through a potential difference of 23 kV. The electrons then pass through a 0.29 T magnetic field that deflects them to the appropriate spot on the screen. Find the magnitude of the maximum magnetic force that an electron can experience.

2. Relevant equations
B=F/QVSin(theta)

3. The attempt at a solution
Since i'm solving for F, i got it by itself:F=BQVSin(theta). I had theta equal to 90, because a charge experiences Fmax when perpendicular to the field. I had q=1.6x10^-19, which is the charge of an electron. I know that the potential difference is 23 kV, but i cannot figure out how to solve for V

2. Jul 15, 2008

### kdrobey

to solve for v, i tried v=(Square root)2q/m. so 2(1.6e-19)/(9.11e-31)=592673.9=v. then F=0.29*(1.6e-19)(592673.9)=2.75e-14

3. Jul 16, 2008

### Defennder

You appear to have missed a variable, that of the potential difference over which the electrons were accelerated. Apart from that your method appears quite all right.