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Max Magnetic Force

  1. Jul 15, 2008 #1
    1. The problem statement, all variables and given/known data
    In a television set, electrons are accelerated from rest through a potential difference of 23 kV. The electrons then pass through a 0.29 T magnetic field that deflects them to the appropriate spot on the screen. Find the magnitude of the maximum magnetic force that an electron can experience.

    2. Relevant equations

    3. The attempt at a solution
    Since i'm solving for F, i got it by itself:F=BQVSin(theta). I had theta equal to 90, because a charge experiences Fmax when perpendicular to the field. I had q=1.6x10^-19, which is the charge of an electron. I know that the potential difference is 23 kV, but i cannot figure out how to solve for V
  2. jcsd
  3. Jul 15, 2008 #2
    to solve for v, i tried v=(Square root)2q/m. so 2(1.6e-19)/(9.11e-31)=592673.9=v. then F=0.29*(1.6e-19)(592673.9)=2.75e-14
  4. Jul 16, 2008 #3


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    Homework Helper

    You appear to have missed a variable, that of the potential difference over which the electrons were accelerated. Apart from that your method appears quite all right.
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