# Max & Min

## Homework Statement

let f(x)=(x+1)^2(x-2)
a)Find the max and Min values of f(x)
b)Find the inflection point of concavity

## Homework Equations

using defferentiation

## The Attempt at a Solution

for part a) differentiate (x+1)^2(x-2) we get ans=3(x-1)(x+1) Plse check for me?
than f'(x)=0 therefore the points i got is x=1 and x=-1 respective??

the second part not sure..plse assist.

You are right about the local max and min. For the second part--all an inflection point is, is where the second derivative (that which we use to determine concavity) is 0. So you would have

$$f''(x)=2(x-2)+4(x+1)=0$$

Can you get it from there?

HallsofIvy