- #1

- 2

- 0

r=5sin(2^)

options

a. max calue r occurs when sin(2^)=1

b. " " sin*2^)=-1

c. min sin(2^)=0

d. min Sin(2^)=-1

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- Thread starter 1672978
- Start date

- #1

- 2

- 0

r=5sin(2^)

options

a. max calue r occurs when sin(2^)=1

b. " " sin*2^)=-1

c. min sin(2^)=0

d. min Sin(2^)=-1

- #2

- 2

- 0

can someone explain what this question means

r=5sin(2^)

options

a. max calue r occurs when sin(2^)=1

b. " " sin*2^)=-1

c. min sin(2^)=0

d. min Sin(2^)=-1

- #3

mathman

Science Advisor

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- 535

Your notation is strange. What is 2^? I also have trouble understanding the options.

- #4

HallsofIvy

Science Advisor

Homework Helper

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- 969

At first I thought that "^" was "degrees" so that sin(2^) was "sin of 2 degrees" but then 5 sin(2 degrees) is a specific number- it would make no sense to talk about "max" and "min" for a single number. Only an expression or function can have "max" or "min" so- what does "sin(2^)" mean?

r=5sin(2^)

options

a. max calue r occurs when sin(2^)=1

b. " " sin*2^)=-1

c. min sin(2^)=0

d. min Sin(2^)=-1

If the problem was actually r= 5sin(2^x), that is [itex]r= 5 sin(2^x)[/itex], then just use the fact that the largest possible value of sine is 1 and the smallest possible value is -1.

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