Homework Help: Max/ min

1672978 · May 1, 2009

can someone explain what this question means
r=5sin(2^)

options
a. max calue r occurs when sin(2^)=1
b. " " sin*2^)=-1
c. min sin(2^)=0
d. min Sin(2^)=-1

1672978 · May 1, 2009

Min Max how to figure what they are ??

can someone explain what this question means
r=5sin(2^)

options
a. max calue r occurs when sin(2^)=1
b. " " sin*2^)=-1
c. min sin(2^)=0
d. min Sin(2^)=-1

mathman · May 1, 2009

Your notation is strange. What is 2^? I also have trouble understanding the options.

HallsofIvy · May 1, 2009

Re: Min Max how to figure what they are ??

1672978 said: ↑

can someone explain what this question means
r=5sin(2^)

options
a. max calue r occurs when sin(2^)=1
b. " " sin*2^)=-1
c. min sin(2^)=0
d. min Sin(2^)=-1

At first I thought that "^" was "degrees" so that sin(2^) was "sin of 2 degrees" but then 5 sin(2 degrees) is a specific number- it would make no sense to talk about "max" and "min" for a single number. Only an expression or function can have "max" or "min" so- what does "sin(2^)" mean?

If the problem was actually r= 5sin(2^x), that is [itex]r= 5 sin(2^x)[/itex], then just use the fact that the largest possible value of sine is 1 and the smallest possible value is -1.

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Homework Help: Max/ min

1672978

1672978

mathman

HallsofIvy