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MAX prove question

  1. Dec 2, 2008 #1
    An is a bounded sequence which converges to 0.
    An>0 for every n.
    prove that in this sequence we have a maximal member
    ??

    again its obvious because if a sequence is descending and it converges from a positive number
    to 0.
    so 0 is the larger lower bound
    and our first member must be the larger

    how to transform it to math?
     
  2. jcsd
  3. Dec 2, 2008 #2
    If it converges to 0, then finitely many members of the sequence take on a different value (that number may be small or large but it is still finite) and the rest of the terms approach 0.
     
  4. Dec 2, 2008 #3
    how to prove it mathematically?
     
  5. Dec 2, 2008 #4
    By combining what you and I wrote and using proper notation
     
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