1. The problem statement, all variables and given/known data Progressive waves are generated on a rope by vibrating vertically the end, P, in simple harmonic motion of amplitude 90 mm. The wavelength of the waves is 1.2 m and they travel along the rope at a speed of 3.6msÂ–1. Assume that the wave motion is not damped. Calculate the maximum speed of point P. 3. The attempt at a solution The actual solution is V=2(pi)xfxA Since f=v/wavelength= 3.0 Hz and A=90x10^-3m the answer is 1.70 m/s I don't understand why this formula is used and where the 2pi has come from. Is it to do with simple harmonic motion? I would be very grateful if someone could help with a derivation of the formula.
oh gosh no I haven't! erm on my physics data sheet there's a similar equation: x=Acos2Pift. hmmm I'll see what comes up when I google the equation you just gave me! Thanks