(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Progressive waves are generated on a rope by vibrating vertically the end, P, in simple

harmonic motion of amplitude 90 mm. The wavelength of the waves

is 1.2 m and they travel along the rope at a speed of 3.6msÂ–1. Assume that the wave motion is not damped.

Calculate the maximum speed of point P.

3. The attempt at a solution

The actual solution is V=2(pi)xfxA

Since f=v/wavelength= 3.0 Hz and A=90x10^-3m the answer is 1.70 m/s

I don't understand why this formula is used and where the 2pi has come from. Is it to do with simple harmonic motion? I would be very grateful if someone could help with a derivation of the formula.

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# Max. speed of particle on wave

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