1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Maxima and Minima

  1. Dec 5, 2005 #1
    Hi I am stuck on this ques. although i have solved and got the ans but i am still facing a problem.
    Find the shortest distance of the point (0,c) from the parabola y=x^2 where 0<= c <= 5
    i got the ans right that is
    (c-0.25)^0.5
    but i have not been able to understand the use of the 0<= c <= 5
    any help?
     
  2. jcsd
  3. Dec 6, 2005 #2
    any help out there?
     
  4. Dec 6, 2005 #3

    HallsofIvy

    User Avatar
    Science Advisor

    Assuming that c> 1/4, I get that. However, notice that your solution makes no sense if c< 1/4! What is the nearest point on the parabola if c< 1/4? (Hint: check the endpoints of the interval of values for y.)
     
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook