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Homework Help: Maxima and Minima

  1. Dec 5, 2005 #1
    Hi I am stuck on this ques. although i have solved and got the ans but i am still facing a problem.
    Find the shortest distance of the point (0,c) from the parabola y=x^2 where 0<= c <= 5
    i got the ans right that is
    (c-0.25)^0.5
    but i have not been able to understand the use of the 0<= c <= 5
    any help?
     
  2. jcsd
  3. Dec 6, 2005 #2
    any help out there?
     
  4. Dec 6, 2005 #3

    HallsofIvy

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    Science Advisor

    Assuming that c> 1/4, I get that. However, notice that your solution makes no sense if c< 1/4! What is the nearest point on the parabola if c< 1/4? (Hint: check the endpoints of the interval of values for y.)
     
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