How can the owners maximize profits by pricing their coffee beans effectively?

  • Thread starter jheld
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In summary: The Attempt at a SolutionSolving for Mocha first..f_x = -100f_y = 40But after that, I get stuck; I am not sure how to relate the $2 cost we were given.What do x and y represent? Your first sentence indicates that these are the per-pound prices, respectively, of Mocha and Kona coffee beans, but then you have two expressions that also involve x and y for the pounds of each type sold. I don't see how the variables in your two weight expressions can be the same as those of the per-pound price.Yeah, it is phrased weird. I
  • #1
jheld
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Homework Statement


Mocha beans are priced at X dollars per pound, and Kona beans at y dollars per pound.
80 - 100x + 40y pounds of Mocha beans sold each week
20 + 60x -35y Kona beans sold each week. Cost of the beans is $2 per lbs of Mocha and $4 of Kona beans to the owners.
How should the owners price the coffee beans in order to maximize their profits?


Homework Equations


Looking for critical points (maximums, extremum).
Take the first derivative of each partial, see what the variable should be for it to be equal to 0.
Then go to the second partials and put them in the Hessian matrix, and solve with the derivative to see what the max should be.


The Attempt at a Solution


Solving for Mocha first..
f_x = -100
f_y = 40
But after that, I get stuck; I am not sure how to relate the $2 cost we were given.
 
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  • #2
What do x and y represent? Your first sentence indicates that these are the per-pound prices, respectively, of Mocha and Kona coffee beans, but then you have two expressions that also involve x and y for the pounds of each type sold. I don't see how the variables in your two weight expressions can be the same as those of the per-pound price.
 
  • #3
Yeah, it is phrased weird. I'll rewrite the entire problem statement just to be sure:
The Java Joint Gourmet Coffee House sells top-of-the-line Arabian Mocha and Hawaiian Kona beans. If Mocha beans are priced at x dollars per pound and Kona beans at y dollars per pound, then market research has shown that each week approximately 80 - 100x + 40y pounds of Mocha benas will be sold and 20 + 60x - 35y pounds of Kona beans will be sold. The wholesale cost to the Java Joint owners is $2 per pound for Mocha beans and $4 per pound for Kona beans. How should the owners price the coffee beans in order to maximize their profits?
 
  • #4
jheld said:

Homework Statement


Mocha beans are priced at X dollars per pound, and Kona beans at y dollars per pound.
80 - 100x + 40y pounds of Mocha beans sold each week
20 + 60x -35y Kona beans sold each week. Cost of the beans is $2 per lbs of Mocha and $4 of Kona beans to the owners.
How should the owners price the coffee beans in order to maximize their profits?


Homework Equations


Looking for critical points (maximums, extremum).
Take the first derivative of each partial, see what the variable should be for it to be equal to 0.
Then go to the second partials and put them in the Hessian matrix, and solve with the derivative to see what the max should be.


The Attempt at a Solution


Solving for Mocha first..
f_x = -100
f_y = 40
But after that, I get stuck; I am not sure how to relate the $2 cost we were given.
How did you get "f_x= -100"? There is no "f" in the problem! Don't just start taking derivatives of what ever formula you see.

The owners want to maximize profits. If x is the price of a pound of Mocha beans and each pound cost $2, then they make a profit of x- 2 dollars on each pound of Mocha beans. If they sell 80 - 100x + 40y pounds of Mocha beans, then the total profit from Mocha beans is "profit per pound times pounds" or [itex]P_M= (x- 2)(80- 100x- 40x)[/itex]. If Y is the price of a pound of Kona beans and each pound cost $4, they make a profit of y- 4 dolars on each pound of Kona beans. If they sell 20 + 60x -35y pounds of Kona beans, they make a profit of [itex]P_K= (y-4)(20+ 6x- 35y)[/itex]. Those are the functions you need to differentiate, giving two equations to solve for x and y.
 
  • #5
Okay, so far I understand. And, just to clarify, I wasn't using f_x and f_y notation for the hell of it, I was just making f the general equation. But, I understand the x - 2 and y -4 in conjunction with the two equations given.

So, I have taken the first (and second order) derivatives of each equation, but from there I am a little stuck. I have a few different points, and thus I am unsure of where they connect.

P_M(x) = -120 - 200x + 40y, where x = 0, y = 3;
P_M(y) = 40x - 80, where x = 2, y = 0;

P_K(x) = 60y - 240, where y = 4;
P_K(y) = 60x - 70y + 160, where x = -8/3, y = 16/7

I have also calculated the 2nd order partial derivatives, but I wanted to make sure that this was on the right track.
 
  • #6
It's on the right track, but to finish it off, you should also apply the second derivative test for partial deriviatives.
 

What is the best way to maximize coffee profits?

The best way to maximize coffee profits is to focus on increasing sales and reducing costs. This can be achieved through effective marketing strategies, optimizing inventory management, and negotiating better prices with suppliers.

How can I increase sales for my coffee business?

To increase sales, it is important to understand your target market and their preferences. Offering unique and high-quality products, providing excellent customer service, and creating a welcoming atmosphere can also attract more customers and boost sales.

What are some cost-cutting measures for a coffee business?

There are several cost-cutting measures that can be implemented in a coffee business, such as optimizing inventory management, reducing waste, negotiating better prices with suppliers, and streamlining operations. Using energy-efficient equipment and implementing sustainable practices can also help save costs in the long run.

How can I effectively market my coffee business?

Effective marketing for a coffee business involves understanding your target market, creating a strong brand image, and utilizing various marketing channels such as social media, email marketing, and partnerships with other businesses. Offering promotions and discounts can also attract new customers and retain existing ones.

What role does customer satisfaction play in maximizing coffee profits?

Customer satisfaction is crucial in maximizing coffee profits as happy customers are more likely to become repeat customers and recommend your business to others. Providing excellent customer service, addressing any concerns promptly, and consistently delivering high-quality products can help improve customer satisfaction and ultimately increase profits.

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