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Maximum amplitude of oscillation of a block

  1. Mar 31, 2004 #1
    I've been staring at this problem for a loonnng time and i just cant figure it out:(.. i would appreciate it if someone could help me...thx! :)

    A large block with mass 26 kg executes
    horizontal simple harmonic motion as it slides
    across a frictionless surface with a frequency
    1:9 Hz : Block smaller block with mass 9 kg
    rests on it, and the
    coefcient of static friction between the two is
    u = 0.459.
    The acceleration of gravity is 9:8.
    What maximum amplitude of oscillation
    can the system have if the block is not to slip?
    Answer in units of cm.
  2. jcsd
  3. Mar 31, 2004 #2


    User Avatar
    Science Advisor

    The weight of the smaller block is 9(9.81) = 88.29 Newtons. The force necessary to overcome the static friction, then is (88.29)(0.459)= 40.52 Newtons. Using "F= ma", that would correspond to an acceleration (of the smaller) block of 40.52= 9a or
    a= 4.50 m/s2. What amplitude would give a maximum acceleration no greater than 4.5 m/s2?
  4. Mar 31, 2004 #3
    thanks...its a little too late to turn it in for my homework because it was due early this morning but at least i understand it now:)
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