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## Homework Statement

An airplane of mass 1280 kg has an engine failure when flying with an airspeed of 135 km/h at an altitude of 2590 m on a calm day. It then glides at a constant glide angle (which is the direction of flight below the horizontal) towards a safe landing at this constant speed of 135 km/h experiencing a drag force of 1310 N that opposes the direction in which the plane is moving.

Please use: g = 9.81 m s-2

Find the magnitude of the maximum distance over the ground the plane can glide while searching for a safe landing spot.

(Further info: the glide angle is 5.99, and the lift force which acts perpendicular to the wings of the plane is 12500).

## The Attempt at a Solution

The correct solution must be 24700 m, can anyone show me how to get this answer?

I tried to first find the time the airplance has before it contacts the ground using the formula

[tex]y=v_{iy}t+\frac{1}{2}at^2[/tex]

[tex]v_{iy}=135 cos 5.9 = 134.2[/tex]

setting the formula equal to zero and solving for t

[tex]0=134.2t+\frac{1}{2}(-9.81)t^2[/tex]

t=0.0731

Then using the formula x=vt to find the maximum horizontal distance

[tex]135 \times 0.073 \neq 24700[/tex]

My method doesn't work...