- #1

Evangeline101

- 112

- 5

## Homework Statement

A spring toy is launched from the ground at 2.3 m/s at an angle of 78° to the ground. What is the maximum height reached by the spring toy?

## Homework Equations

Δ[/B]d

_{v}= v

_{1}Δt + 1/2aΔt

^{2}

## The Attempt at a Solution

[/B]

Calculate time:

Δt = 2.3 m/s / 9.8m/s

^{2}

= 0.23 s

Now calculate vertical motion:

**Δ**d

_{v}= v

_{1}Δt + 1/2aΔt

^{2}*for vertical motion, let (up) be positive

**Δ**d

_{v}= (2.3 m/s) x (0.23s) + 1/2 (-9.8 m/s

^{2}) x (0.23s)

^{2}

**Δ**d

_{v}= 0.27 m [up]

The maximum height reached by the spring toy is 0.27 m [up].

Is this correct? I have a feeling I did it wrong because I did not use the angle they provided and only used the velocity.