1. The problem statement, all variables and given/known data You want to throw an apple to your buddy on the second floor balcony that is 2.2m above where you release the apple. When you throw the apple with a speed of 14m/s at an angle of 55° above the horizontal, it gets to your buddy who catches it on the way down. Find the maximum height of the ball. 2. Relevant equations v=vo+at y=yo+vot+1/2at^2 3. The attempt at a solution I solved for [t] using v=vo+at in the y direction: 0=11.47-9.8t t=1.17s I plugged in the [t] to solve for [y], maximum height: y=2.2+11.5(1.17)+1/2(-9.8)(1.17)^2 y=8.99m This was a quiz from weeks ago. My professor scribbled something about how I shouldn't "add that" in the above equation, which I'm suspecting is the part about 2.2m. If that's the issue, why shouldn't I put 2.2m as my initial y value?