1. The problem statement, all variables and given/known data What is the maximum normal stress in the beam and where is it located? The beam is 1m long, 0.2m high, and 0.05m thick (out of the page). The Modulus of Elasticity is 100Gp. The force is applied at an angle of 20 degrees with horizontal. | |____________ | |- - - - -- - (Imaginary horizontal) |____________| -- 20deg | -- -- F= 2N (the picture is kind of messed up but just imagine a force being applied 20 degrees downward of the horizontal out of the end of the beam, so pretty much straight out of the end of the beam but at a slight angle. 3. The attempt at a solution I calculated that it is 1.879N in x direction and .684N in y direction and that sigx is 187.7 N/m^2 Everywhere I see makes it look like i use equation My/I but I do not know how to calculated y or I and I do not know how any of that plays into this. Any help would be awesome Thanks. 1. The problem statement, all variables and given/known data 2. Relevant equations 3. The attempt at a solution
Good so you have the components of the force. One produces a normal stress which you've found. The vertical component produces a bending stress. You said the dimensions of the beam are 1 m long, 0.2 m high and 0.05 m wide, so if you look at the beam from the front, the dimensions are just 0.2 m x 0.05 m. So what shape does that form? (You can look up I for that section). 'y' is just the distance from the neutral axis. Since the shape is a simple shape, the neutral axis coincides with the centroidal axis. So the maximum value for 'y' would be from the neutral axis to the furthest point. (What distance is this?) I think you should know how to calculate M, the bending moment.
rock.freak667: Perhaps what you need to know, and it's not obvious is that normal stresses arise from both normal forces, and from bending moments. So you need a combined normal stress equation.
Yes, but I did not tell the OP how to combine it, I assumed they'd have the formula to do so since they have the formula for bending.