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Maximum Power in Load of Ideal Transformer

  1. Feb 11, 2010 #1
    1. The problem statement, all variables and given/known data
    The problem can be found http://whites.sdsmt.edu/classes/ee382/homework/382Homework4.pdf" [Broken]. It is the last one.


    2. Relevant equations
    Maximum power occurs when Rp,eff = (N1/N2)2RL = Rs, which means that maximum power occurs when N1/N2 = sqrt(Rs/RL).


    3. The attempt at a solution
    To find Rs, I need to find the Thevenin equivalent at the source, which is simply the same voltage source Vin in series with the 3k resistor; therefore, Rs = 3k.

    RL = 2k + 6k = 8k

    n = N1/N2 = sqrt(Rs/RL) = sqrt(3k/8k) = .61237

    For some reason this doesn't seem right to me. It just seems too easy. Am I doing something wrong, or is this correct?
     
    Last edited by a moderator: May 4, 2017
  2. jcsd
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