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## Homework Statement

Find L & C so that maximum power is delivered to load resistor.

___l 50 ohm l___ ( inductor L )____.____ ( inductor L )___

l . . . . . . . . . . . . .. . . . . . . . . . . l . . . . .. . . . . . . . . . l

10 V ac source . . . . . . . . ( Capacitor C) . . . . . . . l 200 ohm l

l______________________________l__________________l

## Homework Equations

Zi = Zl*

## The Attempt at a Solution

What bugs me is the fact that no source frequency is given.

Im guessing youd go about solving this by dividing the circuit into internal impedance and load impedance, lets pick:

Zi = 50 + jwL

So that the load circuit consists of the cap, other inductor and 200ohm resistor.

The cap is connected in parallel with the inductor and resistor so

1/(jwC) ll (200 + jwL)

((200 + jwl)/(jwC))/(jwC + 200 + jwL)

equating that to Zi*

((200 + jwl)/(jwC))/(jwC + 200 + jwL) = 50 -jwL

Is there any sense to this?

Ps: sorry for the dingy drawing.