1. The problem statement, all variables and given/known data Determine the value of RL that will draw the maximum power from the rest of the circuit shown below. Calculate the maximum power. (This problem was included in our exam this week, and I don't really recall the exact values of the parameters, but I'm pretty sure that the circuit looks more or less like this.) 2. Relevant equations V=IR P=I2R KVL 3. The attempt at a solution Computing for Vab: mesh 1: -10+5I1+15(I1-I3)=0 but I3=0, so I1=2A mesh 2: I2=3Vx but Vx=-6I3, and I3=0, so I2=0 Since no voltage exists in the 3 and 6 ohm resistors, I shorted them and Vab will now be equal to the voltage across the 15 ohm resistor. (Will it? I'm not really sure about this) Therefore, V5ohm=Vab=15I1=15(2) Vab=30V Computing for Rab: mesh 1: 20I1-153=0 --> eqn.1 mesh 2: I2=3Vx but Vx=-6I3 I2=3(-6I3) I2+18I3=0 --> eqn.2 mesh 3: -15I1-3I2+24I3=0 --> eqn. 3 I1=-0.011A I2=0.270A I3=-0.015A I=-I3=-(-0.015) I=0.015A Rab=1/I=1/0.015 Rab=66.667ohms Computing for the maximum power: Pmax=I2Rab=(30/(66.667+66.667))2(66.667) Pmax=3.375W That is what I did. Sirs, did I solve it the right way? I'm especially uncertain about how I solved Vab.