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Homework Help: Maximum shear strain direction

  1. Oct 1, 2011 #1
    1. The problem statement, all variables and given/known data


    2. Relevant equations

    [tex]\gamma_{max} = {\left|{\epsilon_1} - {\epsilon_2} \right|}[/tex]

    3. The attempt at a solution

    I calculated the maximum shear strain to be [itex]200 \mu[/itex].

    For the angle, I don't know exactly how to go about finding it. However, the solution says that the angle is [itex]45^{\circ}[/itex]. Does this mean that all they were asking was to state the angle between the maximum shear plane and the principal plane, which is always [itex]45^{\circ}[/itex]? Or am I supposed to solve for the maximum shear plane angle by first finding the principal plane angle and subtracting [itex]45^{\circ}[/itex] from it?
  2. jcsd
  3. Oct 2, 2011 #2
    You need to get chummy with your buddy the Mohr stress/strain circle... although just looking at the question you could solve it purely from math. I assume you have a solid mechanics or mechanics of materials textbook you could easily find it in there.
  4. Oct 2, 2011 #3
    Our professor explicitly told us not to use Mohr's circle for this question.

    I have tried looking through my mechanics of materials textbook, but couldn't find a way of solving for the direction angle of the maximum shear strain, just with having the principal strains and the maximum shear strain.

    I want to know whether the question was supposed to ask you to state the angle between the maximum shear strain and the angle and the principal plane angle. I know this sounds trivial, but the answer to this problem does say [itex]45^{\circ}[/itex].
  5. Oct 2, 2011 #4


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    temaire: I currently think you worked the problem correctly. I currently think all they were asking for was to state the angle between the maximum shear plane and principal planes, which is always 45 deg.
  6. Oct 2, 2011 #5
    Thank you nvn. That's what I was thinking as well.
  7. Nov 11, 2011 #6
    Always 45 deg. You're right.
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