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Maximum torque

  1. Feb 28, 2015 #1
    1. The problem statement, all variables and given/known data
    2. Relevant equations

    I was given this info
    r=1.5 m
    d=3 m
    F= 50
    angle= 110 degrees


    3. The attempt at a solution
    T=Fsin
    T= (1.5)(50)sin(110)
    T=70 N

    I attempted the solution^ to get (maximum) torque.
     
  2. jcsd
  3. Feb 28, 2015 #2
    i am unsure if my answer is correct or not*
     
  4. Feb 28, 2015 #3

    SteamKing

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    You need to specify units for all the given quantities.

    The units of torque are not newtons. What are they?
     
  5. Feb 28, 2015 #4
    1. The problem statement, all variables and given/known data
    2. Relevant equations

    I was given this info
    r=1.5 m
    d=3 m
    F= 50 N
    angle= 110 degrees


    3. The attempt at a solution
    T=Fsin
    T= (1.5)(50)sin(110)
    T=70 J (joules)

    I attempted the solution^ to get (maximum) torque.
     
  6. Feb 28, 2015 #5

    SteamKing

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    Although mathematically torque and work have the same units, the convention is to use units of F*L when talking about torque, and joules when talking about work.
     
  7. Feb 28, 2015 #6
    thank you for notifying me about the units being used in this problem, so how would i go about getting MAXIMUM TORQUE?
     
  8. Feb 28, 2015 #7

    SteamKing

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    Change the angle of application of the force.
     
  9. Feb 28, 2015 #8
    would it be 180-110=10 degrees
    so
    T=Fsin
    T= (1.5)(50)sin(10)
    T=13.0 J (joules) ???
     
  10. Feb 28, 2015 #9

    SteamKing

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    Are you sure about this calculation?

    Think about it like this For what angle is the sine a maximum?
     
  11. Feb 28, 2015 #10
    90?

    T=Fsin
    T= (1.5)(50)sin(90)
    T=75 (joules)
     
  12. Feb 28, 2015 #11

    CWatters

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  13. Feb 28, 2015 #12

    gneill

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    CWaters is correct, this thread duplicates a question in another thread. This thread is closed.
     
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