1. The problem statement, all variables and given/known data A train travels a distance of 1,2 km between two stations with an average velocity of 43.2 km/h. During it's motion, at the time t1=40s it moved accelerated, then at time t2 it moved uniformly, then at t3=40s it moved uniformly slowed. Find the maximum velocity of the train. The acceleration during the slowed motion is equal in modulus to the acceleration during the accelerated motion. distance=1,2 km average velocity=43.2 km/h t1=40s t3=40s |a3|= a1 Hopefully it makes sense. 2. Relevant equations 3. The attempt at a solution I tried solving it by finding the total time. Ttotal=average velocity/total distance. 1.2/43.2=0.027 h or 97.2 seconds from here i can find t2 which is 97.2-40-40=12.7 after this i'm stuck and don't know what to do next.