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^{2}h/3.

Given that h = 6 - r, how am i to calculate the maximum possible volume by means of integration.

Many thanks, Joe.

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Given that h = 6 - r, how am i to calculate the maximum possible volume by means of integration.

Many thanks, Joe.

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HallsofIvy

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(neither r nor h can be negative which mean r cannot be less than 0 or greater than 6. Technically we should consider the endpoints 0 and 6 but those obviously give minimum volume (a flat disk or a straight line).

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