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Maxwell related equations converted from MKSA units to Gaussian units

  1. Sep 3, 2004 #1
    So here is an example of what I am trying to do.

    We know that div of an E field=p/eo

    where p=charge density and eo=the permittivity of free space. This equation is expressed in MKSA units. In order to convert this into Gaussian units, we must multiply E by 1/sqare root of 4*pi*eo, and multiply p by square root of 4*pi*eo.

    Thus we are left with E= p*4*pi in Gaussian units

    Now where A is a vector field and T is a potential scalar, I know that B=curl of A

    and E=-gradient of T -1/c*dA/dt in the Gaussian unitss. I have to then convert this into MKSA. I am not sure what to do here because unlike the example which I dealt with above, I do not know how to convert both sides of the equation accordingly. Help anyone?
  2. jcsd
  3. Sep 3, 2004 #2


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    This might help.
    http://electron6.phys.utk.edu/phys594/Tools/e&m/summary/maxwell/maxwell.html [Broken]
    ( http://electron6.phys.utk.edu/phys594/ [Broken] for the main page)

    I once tried to come up with a scheme to write the equations in a way that easily showed the conversion.

    For example, I wrote [itex]\nabla\cdot E= \left[ \frac{1}{4\pi\epsilon_0}\right]4\pi \rho [/itex]. However, I never had the time to check that the whole scheme applied to all of electromagnetism was consistent.
    Last edited by a moderator: May 1, 2017
  4. Sep 4, 2004 #3


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