- #1

- 35

- 0

I let u= x^2-4

so du/2 = xdx

granted, the above also gives me x^2=u+4 so, this gives me:

1/2 int u+8 u^-1/2 du

but the professor has:

1/2 int [u^1/2+8 u^-1/2] du

Did I miss the first u^1/2 somewhere??? where did it come from?

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- Thread starter anderma8
- Start date

- #1

- 35

- 0

I let u= x^2-4

so du/2 = xdx

granted, the above also gives me x^2=u+4 so, this gives me:

1/2 int u+8 u^-1/2 du

but the professor has:

1/2 int [u^1/2+8 u^-1/2] du

Did I miss the first u^1/2 somewhere??? where did it come from?

- #2

- 35

- 0

(u+8)u^-1/2= u^1/2 + 8u^-1/2

Sorry about that! I forgot the parenthesis!

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