OBjects A and B are placed on a vertical spring. A has twice the mass as B. If the spring is depressed and released, propelling the objects into the air, then A will:
a) rise 1/4 as high as b
b) rise 1/2 as high as b
c) rise the same amount as b
d) rise twice as much as b
1/2kx², 1/2mv², mgh, projectile equations, etc.
The Attempt at a Solution
I really dont understand the logic in the solution (answer is C). It would make sense to me that the energy from the spring is transfered to kinetic, and then to gravitational potential energy for the masses. In this case, the mass of the objects would make a difference in determining the height (since its "mgh".)
The only reason I can think is that there is more energy transfered from the spring to the heavier block.
If it were just 1 block on the spring, its simply 1/2kx² = mgh, and you plug and chug. In this sense, if each object were sprung up seperately, the lighter one would definitly go higher.
Basically my problem deals with the logic in having both objects on the same spring, and how that affects the calculations/result of energy transfer.