1. The problem statement, all variables and given/known data The crate shown is held against wedge B by a spring. The spring is 96.0% of its original uncompressed lengthl=2.75m, and the spring constant is given ask=1650N/m. The coefficient of static friction at all contacting surfaces is μs=0.150. The mass of the crate is m=22.0kg . The angle is θ=11.0∘. Neglect the mass of the wedge. Assume the crate only moves in the y direction and that wedge A cannot move. Determine the magnitude of the smallest horizontal force P that is necessary to begin moving the crate upward. 2. Relevant equations 3. The attempt at a solution I found the normal from the spring and the weight of the box to be 397N (this is known to be the correct value). Since A can't move, we can draw a FBD of block B. I noticed that I drew the line for the 79 degree angle for f wrong. ignore it. The 79 degrees is supposed to be along the Y-axis. The number is still correct. Sum of the forces in X = 0 = -P + Ncos79 + .15Nsin79 Sum of the forces in Y=0=-397+NSin79 - .15Ncos79 Using a matrix to solve for P we get P=141 N which is incorrect. I've ran out of ideas here. Every way I do it I seem to get the same answer but it supposedly incorrect.