Me Tarzan, You Jane. Force Problem.

  • Thread starter tambourine
  • Start date
  • #26
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here is the answer, which is same with the answer on ur textbook

solutions:
since it told u that the the vine could safetly support combined weight of Tarzan, Jane and Cheeta

therefore, the maximum tension force is the combined weight.

Assuming the mass of Cheeta is m, then Jane is 2m, therefore Tarzan is 4m.

so the maximum tension equals to T=m+2m+4m= 7m

According to Newton's second law, F(net)= mass times acceleration

and F(net)= 7mg-2mg=5mg
so 5mg= 2ma
therefore, the acceleration is 5mg/ 2m=2.5g (g=9.8m/s^2)

since the length of the vine is 60m, therefore the displacement is 60m

because: d= v(initial)t+(1/2)a(t)^2,the initial velocity equals zero.

therefore, t=2.2s
 
  • #27
heyy, I just had this problem on a homework sheet so i was looking around for some help when i came across this forum. thanks for everyone's help, AND the explanations, they really help.

just so you guys know, the official answer, as this question was from a Sir Isaac Newton UW Physics Exam in '75, is t=2.2s so whoever got that answer must be right.

again, thanks for the help!
 

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