Oh I see. Thanks. I have to do it this way because power is a scalar, is it? Why can't I square the value of 1.5A instead?TSny said:
It's not because its a scalar quantity, it's because the mean of the square of a quantity is not equal to the square of the mean of the quantity. For example, for the two numbers 2 and 4 the mean of the square of the numbers is (22 + 42)/2 = 10. But the square of the mean of the numbers is 32 = 9.toforfiltum said:
Thanks for the really neat explanation.TSny said:
The formula for calculating mean power dissipated in a resistor in an AC circuit is P = Vrms * Irms * cos(θ), where Vrms is the root mean square voltage, Irms is the root mean square current, and θ is the phase angle between the voltage and current.
Mean power is the average power dissipated over a complete cycle of an AC circuit, while instantaneous power is the power dissipated at a specific moment in time. Instantaneous power can vary greatly throughout a cycle, but the mean power will remain constant.
The mean power dissipated in a resistor in an AC circuit is affected by the voltage and current amplitudes, the phase angle between them, and the resistance of the resistor.
No, the mean power dissipated in a resistor in an AC circuit is always positive because the cosine of any angle cannot be negative.
A capacitor or inductor can affect the mean power dissipated in a resistor in an AC circuit by changing the phase angle between the voltage and current, which in turn affects the cos(θ) term in the power formula.