when calculating the mean square error i have been using the differential,(adsbygoogle = window.adsbygoogle || []).push({});

if a length measured is x=2 and the error m_{x}=+- 0.005

then x=2+-0.005

if i have x+y where y=3, m_{y}=+-0.02

m_{x+y}=[tex]\sqrt{m_{y}^{2}+m_{x}^{2}}[/tex]

m_{x*y}=[tex]\sqrt{(y*m_{x})^{2}+(x*m_{y})^{2}}[/tex]

but if i have x^2 does this work the same

for example if the area of a rectangle is x*2x can i say 2x^{2}

m_{2x2}=4x*m_{x}

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Mean square error

**Physics Forums | Science Articles, Homework Help, Discussion**