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Homework Help: Mean square error

  1. Feb 7, 2010 #1
    when calculating the mean square error i have been using the differential,

    if a length measured is x=2 and the error mx=+- 0.005

    then x=2+-0.005

    if i have x+y where y=3, my=+-0.02

    mx+y=[tex]\sqrt{my2+mx2}[/tex]

    mx*y=[tex]\sqrt{(y*mx)2+(x*my)2}[/tex]

    but if i have x^2 does this work the same

    for example if the area of a rectangle is x*2x can i say 2x2

    m2x2=4x*mx
     
  2. jcsd
  3. Feb 7, 2010 #2

    Mark44

    Staff: Mentor

    Tip: don't use [ sub] and [ sup] tags inside of [ tex] code. I have reformatted your script to make it more readable. Inside of [ tex] tags, use _{...} for subscripts and ^{...} for superscripts.
    I don't know if this is correct or not. I suggest looking at what your formula for mx*y, and seeing what you get for mx*x in the formula above.
     
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