Mean square error

  • Thread starter Dell
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  • #1
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when calculating the mean square error i have been using the differential,

if a length measured is x=2 and the error mx=+- 0.005

then x=2+-0.005

if i have x+y where y=3, my=+-0.02

mx+y=[tex]\sqrt{my2+mx2}[/tex]

mx*y=[tex]\sqrt{(y*mx)2+(x*my)2}[/tex]

but if i have x^2 does this work the same

for example if the area of a rectangle is x*2x can i say 2x2

m2x2=4x*mx
 

Answers and Replies

  • #2
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6,876
Tip: don't use [ sub] and [ sup] tags inside of [ tex] code. I have reformatted your script to make it more readable. Inside of [ tex] tags, use _{...} for subscripts and ^{...} for superscripts.
when calculating the mean square error i have been using the differential,

if a length measured is x=2 and the error mx=+- 0.005

then x=2+-0.005

if i have x+y where y=3, my=+-0.02

mx+y=[tex]\sqrt{m_y^2+m_x^2}[/tex]

mx*y=[tex]\sqrt{(y*m_x)^2+(x*m_y)^2}[/tex]

but if i have x^2 does this work the same

for example if the area of a rectangle is x*2x can i say 2x2

m2x2=4x*mx
I don't know if this is correct or not. I suggest looking at what your formula for mx*y, and seeing what you get for mx*x in the formula above.
 

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