# Homework Help: Mean square error

1. Feb 7, 2010

### Dell

when calculating the mean square error i have been using the differential,

if a length measured is x=2 and the error mx=+- 0.005

then x=2+-0.005

if i have x+y where y=3, my=+-0.02

mx+y=$$\sqrt{my2+mx2}$$

mx*y=$$\sqrt{(y*mx)2+(x*my)2}$$

but if i have x^2 does this work the same

for example if the area of a rectangle is x*2x can i say 2x2

m2x2=4x*mx

2. Feb 7, 2010

### Staff: Mentor

Tip: don't use [ sub] and [ sup] tags inside of [ tex] code. I have reformatted your script to make it more readable. Inside of [ tex] tags, use _{...} for subscripts and ^{...} for superscripts.
I don't know if this is correct or not. I suggest looking at what your formula for mx*y, and seeing what you get for mx*x in the formula above.