Well the mean-value theorem states that you can find some c in the interval (2,8) such that:
[tex]f'(c) = \frac{f(8)-f(2)}{8-2}[/tex]
Now just note:
[tex]3 \leq f'(c)=\frac{f(8)-f(2)}{8-2} \leq 5[/tex]
We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling We Value Civility
• Positive and compassionate attitudes
• Patience while debating We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving