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Mean Value Theorem Problem

  • Thread starter vee123
  • Start date
  • #1
13
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I'm having a some difficulty with this problem:

Fidn the value(s) of c guaranteed by the Mean Value Theorem for Integrals for the function over the indicated interval:

f(x)=x - 2(square root of x) Interval: [0,2]

I found the integral to be: x^2/2 - 4/3 x^3/2, then I solved for the interval and got 2- 8(square root of 2)/3
then I did this:
f(c)(2-0)= 2- 8(square root of 2)/3

I just want to know if I am doing this correctly because I can't seem to get the right answers (0.4380,1.7908)
 

Answers and Replies

  • #2
281
1
your methods are correct so far.

you should have an equation that involves [itex] c [/itex] and [itex] \sqrt{c} [/itex]

hint: to solve this equation form the quadratic equation in u, by substituting [itex] u = \sqrt{c} [/itex]

-MS
 
Last edited:
  • #3
13
0
Thanks!! I think I know what to do now. I really appreciate it!
 

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