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Mean Value Theorem Problem

  1. Feb 10, 2005 #1
    I'm having a some difficulty with this problem:

    Fidn the value(s) of c guaranteed by the Mean Value Theorem for Integrals for the function over the indicated interval:

    f(x)=x - 2(square root of x) Interval: [0,2]

    I found the integral to be: x^2/2 - 4/3 x^3/2, then I solved for the interval and got 2- 8(square root of 2)/3
    then I did this:
    f(c)(2-0)= 2- 8(square root of 2)/3

    I just want to know if I am doing this correctly because I can't seem to get the right answers (0.4380,1.7908)
  2. jcsd
  3. Feb 10, 2005 #2
    your methods are correct so far.

    you should have an equation that involves [itex] c [/itex] and [itex] \sqrt{c} [/itex]

    hint: to solve this equation form the quadratic equation in u, by substituting [itex] u = \sqrt{c} [/itex]

    Last edited: Feb 10, 2005
  4. Feb 10, 2005 #3
    Thanks!! I think I know what to do now. I really appreciate it!
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