- #1

- 13

- 0

Fidn the value(s) of c guaranteed by the Mean Value Theorem for Integrals for the function over the indicated interval:

**f(x)=x - 2(square root of x) Interval: [0,2]**

I found the integral to be: x^2/2 - 4/3 x^3/2, then I solved for the interval and got 2- 8(square root of 2)/3

then I did this:

f(c)(2-0)= 2- 8(square root of 2)/3

I just want to know if I am doing this correctly because I can't seem to get the right answers (0.4380,1.7908)