- #1
alexepascual
- 371
- 1
I understand that observables in quantum mechanics are represented by hermitian operators, which are converted into a matrix when expressed in a particular basis. I also understand that when the basis used is an eigenbasis of the operator, the matrix becomes diagonal, having the eigenvalues as diagonal elements, and those eigenvalues are the possible results of the measurement.
But I still think I am missing something, that I fail to visualize the connection between the math and the physical process.
I know of three things you can do to a state:
(1) You can unitarily change it, like under a force or just letting time pass
(2) You can make a measurement, which would change the state by eliminating some of its components.
(3) You can make a change of basis, which would leave the state alone and just change your description of it by rotating the frame of reference (in Hilbert space).
But I don't understand how the observable operators relate to the three points above.
I can see how the operator can, in its eigenbasis and when bracketed with the state vector, give a weighted sum of all the possible measurement resuts, which would correspond to the expectation value. But that's the most I can make out of it. And, again, I think I am missing somethhing.
If a state (pure) is represented by a state vector, and operators operate on state vectors to yield other state vectors; what is that operators corresponding to measurables do to the state vector? It can't be a change of basis because this is accomplished by a unitary operator. It can't be a real measurement because the operator is not projecting the state vector on a basis, unless it is already in its eigenbasis. And the meaning of these operators become even less clear when they appear multiplied times each other like in the conmutators.
I have started to explore this problem with spin operators, but an elementary treatment has not answered my questions. I realize that after reading a lot about angular momentum I might get to the point I understand. But I thought there should be some explanation of this independent of the particular states under consideration.
I am really confused. All I have read doesn't seem to clarify this puzzle.
I'll appreciate your help guys,
--Alex--
But I still think I am missing something, that I fail to visualize the connection between the math and the physical process.
I know of three things you can do to a state:
(1) You can unitarily change it, like under a force or just letting time pass
(2) You can make a measurement, which would change the state by eliminating some of its components.
(3) You can make a change of basis, which would leave the state alone and just change your description of it by rotating the frame of reference (in Hilbert space).
But I don't understand how the observable operators relate to the three points above.
I can see how the operator can, in its eigenbasis and when bracketed with the state vector, give a weighted sum of all the possible measurement resuts, which would correspond to the expectation value. But that's the most I can make out of it. And, again, I think I am missing somethhing.
If a state (pure) is represented by a state vector, and operators operate on state vectors to yield other state vectors; what is that operators corresponding to measurables do to the state vector? It can't be a change of basis because this is accomplished by a unitary operator. It can't be a real measurement because the operator is not projecting the state vector on a basis, unless it is already in its eigenbasis. And the meaning of these operators become even less clear when they appear multiplied times each other like in the conmutators.
I have started to explore this problem with spin operators, but an elementary treatment has not answered my questions. I realize that after reading a lot about angular momentum I might get to the point I understand. But I thought there should be some explanation of this independent of the particular states under consideration.
I am really confused. All I have read doesn't seem to clarify this puzzle.
I'll appreciate your help guys,
--Alex--